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Twelve days of christmas total gifts




twelve days of christmas total gifts

a partridge in a pear.
7 x 6 42, she gets 8 maids a-milking on the last 5 days.6 x 7 42, she gets 7 swans a-swimming on the last 6 days.On the eleventh day she gets gifts.On the third day she gets gifts.See the 59 Comments below.Another way of writing this is: On the first day, 1 present.The first few lines go like this: On the first day of Christmas, my true love sent.The answer reveals a surprising mathematical pattern!On the 12th hemingway nobel prize day, the number of presents will be If my true love gave me the presents in this pattern for 30 days, I would have this number of presents: If it was 100 days, I would have this number of presents: Good deal.In the Christmas song, "The 12 Days of Christmas how many total gifts does her true love give to her?
On the ninth day of Christmas, my true love sent to me Nine ladies dancing, Eight maids a-milking, Seven swans a-swimming, Six geese a-laying, Five golden rings, Four calling birds, Three French hens, Two turtle doves, And a partridge in a pear tree.
Here's one of the possible ways of doing this.
On the second day of Christmas (26th December my true love sent to me three presents.
How many presents then?
On the second day of Christmas, my true love sent.
12 x 1 12 Total 364 She gets a total of 364 gifts.
Of course, we could just start adding with our calculator, but what if my true love is very generous, and starts giving me presents for 30 days after Christmas?We are adding the triangular numbers.Lyrics of the Twelve Days of Christmas On the first day of Christmas, my true love sent to me A partridge in a pear tree.On the fifth day she gets gifts.On the seventh day of Christmas, my true love sent to me Seven swans a-swimming, Six geese a-laying, Five golden rings, Four calling birds, Three French hens, Two turtle doves, And a partridge in a pear tree.Have you ever wondered about how many gifts the singer received in the famous Twelve Days of Christmas song? .The formula for the sum to n terms of an arithmetic progression with first term a and common difference d is: Substituting our values, we have: So ( ) 6 2(5) 6 60 But remember, this is 3 times what we really want, so the.I will divide by 3 later to cater for this).


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